8x-(x^2-8x)=0

Solution for 8x-(x^2-8x)=0 equation:

8x-(x^2-8x)=0

We get rid of parentheses

-x^2+8x+8x=0

We add all the numbers together, and all the variables

-1x^2+16x=0

a = -1; b = 16; c = 0;
Δ = b2-4ac
Δ = 162-4·(-1)·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-16}{2*-1}=\frac{-32}{-2}
=+16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+16}{2*-1}=\frac{0}{-2}
=0
$